Is quadrilateral ABCD, seg AB= seg AD, seg BC = seg BD
/_ BAD = 70° /_ BCD = BCD = 65° find m/_ADC
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In the figure, ∠BAD = 70
o
, ∠ABD = 56
o
and ∠ADC = 72
o
. Calculate (i) ∠BDC (ii) ∠BCD (iii) ∠CBD
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ANSWER
Given,
∠BAD=70
∠ABD=56
∠ADC=72
ABCD is a cyclic quadrilateral.We know, that sum of opposite angles of a cyclic quadrilateral is 180.
Therefore,
∠BAD+∠BCD=180
=>∠BCD=180−70
=110 (ii)
∠ADC+∠ABC=180
=>72+∠ABD+∠DBC=180
=>72+56+∠CBD=180
=>∠CBD=180−128
=52
In △BCD,
∠BCD+∠DBC+∠BDC=180
=>110+52+∠BDC=180
=>∠BDC=18 (i)
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