Math, asked by rimiranjita72, 4 months ago

Is quadrilateral ABCD, seg AB= seg AD, seg BC = seg BD

/_ BAD = 70° /_ BCD = BCD = 65° find m/_ADC​

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Answered by stuti26411
0

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In the figure, ∠BAD = 70

o

, ∠ABD = 56

o

and ∠ADC = 72

o

. Calculate (i) ∠BDC (ii) ∠BCD (iii) ∠CBD

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ANSWER

Given,

∠BAD=70

∠ABD=56

∠ADC=72

ABCD is a cyclic quadrilateral.We know, that sum of opposite angles of a cyclic quadrilateral is 180.

Therefore,

∠BAD+∠BCD=180

=>∠BCD=180−70

=110 (ii)

∠ADC+∠ABC=180

=>72+∠ABD+∠DBC=180

=>72+56+∠CBD=180

=>∠CBD=180−128

=52

In △BCD,

∠BCD+∠DBC+∠BDC=180

=>110+52+∠BDC=180

=>∠BDC=18 (i)

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