Question

is right angle triangle has a largest side is 13 cm and one of the side containing the right angle is 12 cm is area in cm square is

Answer 1

SOLUTION :

Let the mane of the triangle be ABC triangle.

BC is base = 12 cm,

AC is hypotenuse = 13 cm

AB is height

Now,

$\bf In\: triangle ABC \\(AB)^{2}+(BC)^{2}=(AC)^{2}\\\\(AB)^{2}+(12)^{2}=(13)^{2}\\\\(AB)^{2}+144=169\\ \\(AB)^{2}=169-144\\ \\(AB)^{2}=25\\\\AB=\sqrt{25}\\ \\AB=5cm$

We got,

Base = BC = 12 cm, and Height = AB = 5 cm

Now,

Area = $\bf \frac{1}{2} \times base \times height\\ \\= \frac{1}{2} \times 12 \times 5\\\\= 30cm^{2}$