Is sec square thita + tan square theta = x then tan theta =
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Answer:
tanθ=(−1±i√3)/2
Step-by-step explanation:
Write
sec^2θ=1+tan^2θ
, so that given equation becomes tan^2θ+tanθ+1=0
. Solving this for tanθ
we would have tanθ=[−1±√(1−4)]/2
=(−1±i√3)/2
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