Question

Is series an A.P √3, √6, √9, √2... an
AP? give reason?


It's urgent​

Answer 1

Answer:

The following sequence is not in an A.P .

Step-by-step explanation:

First of all, all the AP's only exist if there is a common difference. So if we compute the common difference of √6 and √3 we get,

d = √6 - √3

= √3 ( √2 - 1 ) ------------- 1

d = √9 - √6

= 3 - √6

= √12 - √9

= 2√3 - 3 --------------- 2

So, if we look at 1 and 2, we find that the common difference (d) is not the same. So, we can conclude that the pattern is not in an AP.