Question

is sin A =1/3 , then cosA cosec A + tan A secA

Answer 1

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Sin A = 1/3

cosecA = 3

Cos ^2A = 1- sin^2 A

Cos^2 A = 1 - (1/3)^2
Cos ^2 A = 1- 1/ 9
Cos ^2 A = 8/ 9
Cos A = √8/ 9

Cos A = √8/ 3
Sec A = 3/√8

Tan A = 1/√8

Cot A = √8

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