is sin a is equal to 3 upon 4, calculate Cos A and 10 a
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Answered by
7
Answer:
cos A=√7/4
tan A=3/√7
Step-by-step explanation:
sin A=3/4
cos A=√(1-sin²A)=√(1-(3/4)²)
=√(1-(9/16))=√((16-9)/16)=√7/4
tan A= sin A/cos A=(3/4)÷(√7/4)=3/√7
Answered by
7
Answer:
hey mate here is your answer....
Step-by-step explanation:
▶️ Let ∆ABC be a right angled triangle at B.
➡️ We know that sinA = BC / AC = 3 / 4
➡️ Let BC be 3k and AC will be 4k , where k is a positive real number.
➡️ By Pythagoras theorem we get
- AC ² = AB² + BC²
- (4k)² = AB² + (3k)²
- 16k² = AB² + 9k²
- AB² = 16k² - 9k²
- AB² = 7k²
- AB = √7k
▶️ cosA = AB / AC = √7k / 4k = √7 / 4
▶️ tanA = BC / AB = 3k / √7k = 3 / √7
Hope it helps!✌️
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