Is sin a is inversely proportional to cotA?
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From given question,
cosA
cosB
=
b
a
cosB
a
=
cosA
b
sin(90
0
−B)
a
=
sin(90
0
−A)
b
Following sine rule, we get
90
0
−B=A
A+B=90
0
180
0
−C=90
0
C=90
0
....right angled triangle.
Now if a=b, then A=B ... isosceles.
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