is sin C = cos A in right angled isosceles triangle ABC where angleB=90degrees? explain with reason
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sum of angles A + B + C = 180 deg
angle B = 90 deg
So angles A + C = 90 deg
angle A = 90 deg - angle C
Cos A = Cos (90- C) = Sin C
angle B = 90 deg
So angles A + C = 90 deg
angle A = 90 deg - angle C
Cos A = Cos (90- C) = Sin C
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