Is sin theta/ 1-cos theta=cot (theta/2)?
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your LHS is equal to RHS cot theta /2
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Step-by-step explanation:
All you need are the following formulas:
sin(2A)=2sin(A)cos(A) and cos(2A)=1−2sin2(A)
Now take A=θ/2 to get that
sin(θ)=2sin(θ/2)cos(θ/2) and cos(θ)=1−2sin2(θ/2)
Now plugging this into your equation, we get that
sin(θ)1−cos(θ)=2sin(θ/2)cos(θ/2)2sin2(θ/2)=cos(θ/2)sin(θ/2)=cot(θ/2)
Hope it helps.
Thank you.
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