Question

is sin theta = 3/5, then find (I) cos theta (ii) Tan theta (iii) sin²theta+cos²theta​

Answer 1

Answer:

1) cos θ = 4/5

2) tan θ = 3/4

3) sin²θ + cos² θ​ = 1

Step-by-step explanation:

sin θ = 3/5

sine = opposite/hypotenuse

opposite = 3, hypotenuse = 5

5^2 = 3^2 + adjacent^2 (Pythagorean theorem)

adjacent^2 = 25 - 9 = 16

adjacent = 4

1) cosine = adjacent/hypotenuse

cos θ = 4/5

2) tangent = opposite/adjacent

tan θ = 3/4

3) sin²θ + cos² θ​ = (3/5)^2 + (4/5)^2

= 9/25 + 16/25 = 25/25 = 1