Question

is sinA =sinB & cosA =cosB,then​

Answer 1

hope It helps u dear

sinA−sinB=0 and cosA−cosB=0

⇒ 2sin

2

A−B

cos

2

A+B

=0

and 2sin

2

A+B

cos

2

B−A

=0

We observe that the common factor gives sin

2

A−B

=0.

Thus,

2

A−B

=nπ, n∈Z

A−B=2nπ, n∈Z

A=2nπ+B, n∈Z