Is square root 1 minus sine squared theta = cos Θ true? If so, in which quadrants does angle Θ terminate?
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Answered by
10
Hey there !!!
sin²θ+cos²θ=1
cos²θ=1-sin²θ
cosθ=√(1-sin²θ)-----Equation 1
Equation 1 is defined only when 0 ≤√1-sin²θ≤1 as negative sqrt is not defined so √1-sin²θ must be greater than or equal to 0 and maximum value of cosθ is 1 so √1-sin²θ is ≤1
cosθ is negative in 2nd and 3rd quadrants so θ can't take any value lying in 2nd and 3rd quadrants.
Hope this helped you............
sin²θ+cos²θ=1
cos²θ=1-sin²θ
cosθ=√(1-sin²θ)-----Equation 1
Equation 1 is defined only when 0 ≤√1-sin²θ≤1 as negative sqrt is not defined so √1-sin²θ must be greater than or equal to 0 and maximum value of cosθ is 1 so √1-sin²θ is ≤1
cosθ is negative in 2nd and 3rd quadrants so θ can't take any value lying in 2nd and 3rd quadrants.
Hope this helped you............
Answered by
2
Answer:
The answer of it's question is Cos theeta
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