is
Suppose
s
for
every
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defined and differentiable
and f(x) to as 1000
9 (x) = f(x+1)-f(x)
that
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prove .
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Answers
Answered by
0
Answer:
9(x) = f(x+1)-f(x)
Step-by-step explanation:
9x = fx + f - fx
9x=f
x=f/9
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