Question

Is $(p-q)^2 = (q-p)^2$ ?

Answer 1

➡ (p - q)² = (q - p)²

➡ p² + q² - 2pq = q² + p² - 2pq

➡ 0

Step-by-step explanation:

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Answer 2

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Is $(p-q)^2 = (q-p)^2$ ?

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Yes,are equal

${(p - q)}^{2} = {(q - p)}^{2}$

${(p - q)}^{2} = {p}^{2} + {q}^{2} - 2pq$

let's take an example to understand:-

let's p=2 & q=1

${(2 - 1)}^{2} = {2}^{2} + {1}^{2} - 2(2)(1) = 5 - 4 = 1$

${(q - p)}^{2} = {(1 - 2)}^{2} = {1}^{2} + {2}^{2} - 2(1)(2) = 5 - 4 = 1$

It is verified ...

Hope it helps you..!!!

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