is that prove that under root 3 + under root 5 is irrational
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Answered by
1
your answer is here:
under root 3 and 5 do not have there root so they are irrational number
hope it will helpful to you!!!!!!!!!!!
under root 3 and 5 do not have there root so they are irrational number
hope it will helpful to you!!!!!!!!!!!
Answered by
0
let us suppose 3+root 5 is rational.
=>3+root 5 is in the form of p/q where p and q are integers and q is not =0
=>root5=p/q-3
=>root 5=p-3q/q
as p, q and 3 are integers p-3q/3 is a rational number.
=>root 5 is a rational number.
but we know that root 5 is an irrational number.
this is an contradiction.
this contradiction has arisen because of our wrong assumption that 3+root 5 is a rational number.
hence 3+ root 5 is an irrational number.
=>3+root 5 is in the form of p/q where p and q are integers and q is not =0
=>root5=p/q-3
=>root 5=p-3q/q
as p, q and 3 are integers p-3q/3 is a rational number.
=>root 5 is a rational number.
but we know that root 5 is an irrational number.
this is an contradiction.
this contradiction has arisen because of our wrong assumption that 3+root 5 is a rational number.
hence 3+ root 5 is an irrational number.
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