Question

is the 68th term of AP is 7,10,13​

Answer 1

Answer:

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Answer 2

Answer:

No

Step-by-step explanation:

In the given problem

We need to find whether it is a term of the

A.P. Or not.

So, here we will use the formula,

$an = a + (n - 1)d$

Here, A.P Is 7, 10, 13

an= 68

a= 7

Now,

Common Difference(d) = a1 - a

= 10 - 7

= 3

Thus using the above formula mentioned

we get.

68 = 7 + ( n - 1 ) 3

68 - 7 = 3n - 3

61 + 3 = 3n

n = 64÷ 3

Since the value of n is a fraction

Thus 68 is not the term of the given A.P

Therefore The Answer Is No.

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