Question

...... is the 8bit form for the binary number 111​

Answer 1

Answer:

binary representation of 111 is 1101111

As we are taking 0 based indexing and we will start counting from LSB(right most) so 8th bit is 0.

111 =2^0+2^1 +2^2+2^3+2^5+2^6 therefore these bits are set and remaining are zero.

Another simple way is you want check 8th bit so calculate 2^7 which is obviously grater than 111 so it can never be set.

Hope this helps✌