Question

is the answer 60 or 16?
please help with an explanation.​

Answer 1

Question :

Two particles A and B are released from same height at t = 0 and t = 2 seconds respectively. Distance between two particles at t = 4 seconds is

Answer :

Since acceleration due to gravity has constant value, we can apply equation of kinematics to solve this question$.$

★ Second equation of kinematics :

• s = ut + 1/2(gt²)

s denotes distance

u denotes initial velocity

t denotes time

g denotes acc. due to gravity

★ For a body falling freely under the action of gravity, g is taken positive. (u = 0)

⧪ Distance covered by A :

➠ s = ut + 1/2(gt²)

➠ s = (0×4) + 1/2(10×4²)

➠ s = 160/2

➠ s = 80 m

⧪ Distance covered by particle B :

→ s' = ut' + 1/2(gt'²)

For particle B : t' = 4 - 2 = 2s

→ s' = (0×2) + 1/2(10×2²)

→ s' = 40/2

→ s' = 20m

⧪ Distance b/w A and B after 4s :

➙ d = s - s'

➙ d = 80 - 20

➙ d = 60m

∴ (C) is the correct answer!

Cheers!