Question

Is the Answer correct..​

Answer 1

Answer:

yes the answer is correct

Answer 2

Question

$\sf{D = \left|\begin{array}{c c c} 3 & -2& 1 \\ 3 & -1&-2\\3&-2&-3\end{array}\right|}$

$\sf\huge\bold{Solution}$

$\sf{D = \left|\begin{array}{c c c} 3 & -2& 1 \\ 3 & -1&-2\\3&-2&-3\end{array}\right|}$

Now cross multiply with determinant values.

3$\sf{\left|\begin{array}{c c c} -1 & -2 \\ -2 & -3\end{array}\right|}$-(-2)$\sf{ \left|\begin{array}{c c c} 3& -2 \\ 3& -3\end{array}\right|}$+1$\sf{ \left|\begin{array}{c c c} 3& -1 \\ 3 & -2\end{array}\right|}$

$\sf \longmapsto3[ - 3 \times - 1 - ( - 2 \times - 2)]- ( - 2)[- 3 \times 3 - ( - 6)] + 1[- 6 - ( - 3)]$

$\sf \longmapsto3[3 - (4)] + 2( - 9 + 6) + 1( - 6 + 3)$

$\sf \longmapsto3( - 1) + 2( - 3) + 1( - 3)$

$\sf \longmapsto - 3 - 6 - 3$

$\sf \longmapsto - 3 - 9 = - 12$

Your answer is correct!!