Question

is the area of an isosceles triangle is doubled then its area ​

Answer 1

Explanation:

ANSWER

Let the sides of triangle is a,b,c

Then area of triangle =

s(s−a)(s−b)(s−c)

where s=

2

1

(a+b+c)

If sides are doubled the new sides 2a,2b,2c

Then S=

2

1

(2a+2b+2c)⇒2×

2

1

(a+b+c)=2s

Then area of new triangle =$$\sqrt{S(S-2a)(S-2b)(S-2c)}= \sqrt{2s(2s-2a)(2s-2b)(2s-2c)}=\sqrt{16}s(s-a)(s-b)(s-c)= 4\sqrt{s(s-a)(s-b)(s-c)}

Then area of new triangle =4 times of old triangle.

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