Question

is the base angles of an isosceles trapezium is 56 degree each what is the measures of the other two angles​

Answer 1

Answer:

Here is your answer:

Step-by-step explanation:

Let ABCD be the isosceles trapezium, where AC║BD

Let ∠ABD be the base angle = 56°

∠ABD = ∠CDB = 56°     ( base angles of isosceles triangles are equal)

Consider AC║BD  and AB as transversal

⇒ ∠CAB + ∠ABD = 180°    (co- interior angles)

⇒ ∠CAB + 56° = 180°

⇒ ∠CAB = 180° - 56°

              = 124°

⇒∠CAB = ∠DCA = 124°        (base angles- second pair)

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Answer 2

Step-by-step explanation:

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