Is the below function one-one and also find the range.
f(x)=x²+3;-2≤x≤2,x∈Z
Sekher12 don't answer please any other user answer correctly no spams
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f(-2)=(-2)²+3=4+3=7,
f(-1)=(-1)²+4=1+3=4,
f(0)=(0)²+3=0+3=3,
f(1)=(1)²+3=1+3=4,
f(2)=(2)²-4+3=7,
This is not a one-one function .Since-2,2 have the same image 7 and -1,1 have the same image 4.
Hope it will not help you madam.
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