Is the "divides" relation on the set of positive integers transitive ? What is reflexive and symmetric closure of a relation? (R:=(a,b) {a>b} on a set of positive integers ?
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Answer:
Step-by-step explanation:
the smallest of five consecutive integers even?
1) The product of 5 integers is 0
2) The sum of 5 integers is 0.
can anyone explain this question.
thanks
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codesnooker
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by CODESNOOKER » THU MAY 15, 2008 4:45 AM
Answer is (B).
Condition 1:
Product of five consecutive integer = 0.
-1 X 0 X 1 X 2 X 3 = 0 (The smallest integer is -ve ODD integer)
Therefore INSUFFICIENT.
Condition 2:
Sum of five consecutive integer = 0
-2 - 1 + 0 + 1 + 2 = 0 (none other than value can satisfy this condition). The smallest integer is -ve EVEN. Hence SUFFICIENT.
Therefore answer is (B)
J!
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aatech
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by AATECH » THU MAY 15, 2008 6:15 AM
Stmt 1 - Product of 5 integers is 0 means at least one no is zero. Doesn't matter whether the
smallest no is ODD or EVEN - NOT SUFF
Stmt2 - -2, -1 0 1 2 is the only set of five consecutive nos that will have sum 0 and smallest no
is even so SUFF
ANS B
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Stuart@KaplanGMAT
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by STUART@KAPLANGMAT » THU MAY 15, 2008 1:27 PM
codesnooker wrote:
Answer is (B).
Condition 1:
Product of five consecutive integer = 0.
-1 X 0 X 1 X 2 X 3 = 0 (The smallest integer
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