Question

is the length and breadth of a rectangle are doubled how many times the perimeter of the rectangle with that of a new rectangle be​

Answer 1

Answer:

Let the old rectangle's length be L and breath be B

Perimeter, P1 = 2(L+B). ______(1)

When Length and breath is doubled length and breath will be 2L and 2B respectively

Perimeter, P2 = 2(2L+2B)

P2 = 4(L+B). ______(2)

dividing equation (2) by (1)

we get,

P2/P1 = 4(L+B)/2(L+B)

P2=2×P1

The new rectangle will be 2 times the old rectangle