is the length of the diagonals of a rhombus are 30 M and 16 m find the side and area of Rhombus
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□ ABCD is a rhombus
AC = 30m
BD = 16m
AO = 1/2 × AC
( Reason ? Diagonal of a rhombus
are perpendicular
bisector of each other)
AO = 1/2 × 30
AO = 15m
Similarly , OD = 8m
In /_\ AOD
( AD )^2 = ( AO )^2 + ( OD )^2
( AD )^2 = ( 15 )^2 + ( 8 )^2
( AD )^2 = 225 + 64
( AD )^2 = 289
AD = sqrt 289
AD = 17m
Area = 1/2 ( diagonal 1 × diagonal 2 )
Area = 1/2 ( 30 × 8 )
Area = 1/2 ( 240 )
Area = 1/2 × 240
Area = 120m^2
AC = 30m
BD = 16m
AO = 1/2 × AC
( Reason ? Diagonal of a rhombus
are perpendicular
bisector of each other)
AO = 1/2 × 30
AO = 15m
Similarly , OD = 8m
In /_\ AOD
( AD )^2 = ( AO )^2 + ( OD )^2
( AD )^2 = ( 15 )^2 + ( 8 )^2
( AD )^2 = 225 + 64
( AD )^2 = 289
AD = sqrt 289
AD = 17m
Area = 1/2 ( diagonal 1 × diagonal 2 )
Area = 1/2 ( 30 × 8 )
Area = 1/2 ( 240 )
Area = 1/2 × 240
Area = 120m^2
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