Question

Is the line passing through the points A(-2, 3) and B(4, 1) perpendicular to the line 3x - y = 1

Answer 1

Slope of the line l1 joining (x1,y1)=
(-2,3) and (x2,y2)= (4,1) is given by m1 =y2-
y1x2-
x1=1-34+2=-26=-13Now the equation of the se
+1 ⇒ y=3x-1 By comparing with it with y=m2x
+c we get m2=3Now since m1m2=-13×3 =-1 He
(-2,3) and (x2,y2)= (4,1) is given by P=x2+x12,y
(1,2)Now second line l2 : 3x=y
+1 is satisfied by the point P (1,2) ,because 3×1=
+1 . Hence line 3x=y
+1 bisect The the line l1 joining (x1,y1)=
(-2,3) and (x2,y2)= (4,1).

Answer 2

Answer:

Yes, the lines are perpendicular.

Step-by-step explanation:

coordinates of Line1 are A(-2,3) & B(4,1)

slope(m1) = (y2-y1)/(x2-x1)

= 1-3/4-(-2)

= -1/3

Line2:- 3x=y+1

y = 3x-1

by comparing to y=mx+c

slope(m2) = 3

thus, if the line are perpendicular then

m1×m2 = -1

-1/3×3 = -1

-1 = -1

hence ,the lines are perpendicular.

HOPE IT'LL HELP YOU!