Question

is the molality of chloroform chcl3 in Benzene C6 H6 is 5.18 then mole fraction of chloroform in the solution is​

Answer 1

Hey Dear,

◆ Answer -

X2 = 0.2878

● Explanation -

Molality of the solution is given by -

Molality = moles of solute / mass of solvent

5.18 m solution means 5.18 moles of CHCl3 is dissolved in 1 kg of C6H6.

Moles of benzene are calculated as -

Moles (C6H6) = given weight / molar mass

n1 = 1000 / 78

n1 = 12.82 mol

Mole fraction of chloroform in solution is calculated by -

X2 = n2 / (n1 + n2)

X2 = 5.18 / (12.82 + 5.18)

X2 = 5.18 / 18

X2 = 0.2878

Therefore, mole fraction of CHCl3 in C6H6 solution is 0.2878 .

Thanks for asking...