Question

Is the point (-1, -2) inside, on, or outside the circle with equation (x+2)^2 + (y-3)^2 = 8? Justify your answer.

Answer 1

Answer:

Step-by-step explanation:

If the point is on the circle it will satisfy the equation. If the point is inside the circle then the value will be less than 8 and if its outside the value will be greater than 8.

(x+2)^2 + (y-3)^2 = 8

(-1+2)^2 + (-2-3)^2 = 8

1 + 25 = 8

. 26>8

So the point is outside the circle.