Question

is the root of the equation x^2-8x+m=0 exceeds The Other by 4 then the value of m is ​

Answer 1

Answer:

Step-by-step explanation:

let a and b be the roots of x^2 - 8x + m and let b = a + 4. then,

a + (a + 4) = 8 and a(a + 4) = m

then

2a = 4 and a(a + 4) = m

then

a = 2 and m = 2(2 + 4) = 2 × 6 = 12.

Answer 2

Answer:

Value of m is 12.

Step-by-step explanation:

let p and q be the roots of x² - 8x + m = 0

And according to question q = p + 4.

By comparing above quadratic equation with ax² + bx + c = 0

a = 1, b = -8, c = m

∵Sum of roots = -b/a

p + q = -(-8)/1

p + (p + 4) = 8

2p = 4

p = 2

∵ Multiplication of roots = c/a

p × q = m/1

p(p + 4) = m

By putting value of p in above equation

2(2 + 4) = m

m = 12

So value of m is 12.

#SPJ2