Question

is the root of the equation x3-6x2+5x+12=0 a) 5 b) 6 c) 3 d) 0​

Answer 1

Answer:

b. 6

Step-by-step explanation:

hope it will be right

Answer 2

Step-by-step explanation:

STEP1:Equation at the end of step 1

(((x3) - (2•3x2)) + 5x) + 12 = 0

STEP2:Checking for a perfect cube

 2.1    x3-6x2+5x+12  is not a perfect cube

Trying to factor by pulling out :

 2.2      Factoring:  x3-6x2+5x+12 

Thoughtfully split the expression at hand into groups, each group having two terms :

Group 1:  5x+12 

Group 2:  -6x2+x3 

Pull out from each group separately :

Group 1:   (5x+12) • (1)

Group 2:   (x-6) • (x2)