Question

is the sequence having nth term an=2n-1 an Ap ? if so find first term and common difference.

Answer 1

Hi...☺

Here is your answers..✌

GIVEN THAT,

$a_{n} = 2n - 1 \\ \\for \: n = 1 \\ we \: have \: \\ \\ a_{1} = 2(1) - 1 = 2 - 1 \\ \\ a_{1} = 1 \\ \\ for \: n = 2 \\ we \: have \: \\ \\ a_{2} = 2(2) - 1 = 4 - 1 \\ \\ a_{2} = 3 \\ \\ therefore\: \\ d = a_{2} - a_{1} \\ \\ d \: = 3 - 1 \\ \\ d = 2$

Hence,

First term = a1 = 1

And, Common diff. = d = 2

Answer 2

Given:

nth term of an AP is $a_n=2n-1$

To find:

The first term and common difference

Solution:

$a_n=2n-1$

Substitute n = 1.

$a_1=2(1)-1$

$a_1=1$

First term of an AP is 1.

Substitute n = 2.

$a_2=2(2)-1$

$a_2=3$

Second term of an AP is 3.

Common difference = $a_2-a_1$

                                  = 3 - 1

                                  = 2

Hence first term is 1 and common difference is 2.

To learn more...

1. Is the sequence having nth term an=2n-1 an Ap ? if so find first term and common difference.

https://brainly.in/question/3332219

2. The nth term of a sequence is given by an= 2n+7. show that it is an A.P. Also, find its 7th term.

https://brainly.in/question/5541064