Question

is the sequence
$is \: the \: sequence \sqrt{3} \sqrt{6} \sqrt{9} \sqrt{12} form an \: arithmetic \: progression \:$
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Answer 1

let / be under root

/6-/3=/3(/2-1)=d1

/9-/6=/3(/3-/2) =d2

/12-/9=/3(/4-/3) =d3

if it is in ap than d1 must be equal to d2

but d1 does not equal d2