Is the Sequnce 3/2,1/2,-1/2,-3/3,...
is
an An AP? Justify
Answers
Given series of numbers will form an A.P. if d
Given series of numbers will form an A.P. if d 1
Given series of numbers will form an A.P. if d 1
Given series of numbers will form an A.P. if d 1 =d
Given series of numbers will form an A.P. if d 1 =d 2
Given series of numbers will form an A.P. if d 1 =d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d
Given series of numbers will form an A.P. if d 1 =d 2 =d 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2
Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2 Hence, the given form of numbers will not form an A.P.
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Answer:
No
Step-by-step explanation:
A sequence is said to be in an AP if it's common difference(d) is same.
so,
1/2 - 3/2 = -1
-1/2 - 1/2 = -1
-3/3 - (-1/2) = -1/2