Math, asked by kalpanavyas6505, 4 months ago

Is the Sequnce 3/2,1/2,-1/2,-3/3,...
is
an An AP? Justify​

Answers

Answered by shehzadsiddiqui2005
1

Given series of numbers will form an A.P. if d

Given series of numbers will form an A.P. if d 1

Given series of numbers will form an A.P. if d 1

Given series of numbers will form an A.P. if d 1 =d

Given series of numbers will form an A.P. if d 1 =d 2

Given series of numbers will form an A.P. if d 1 =d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d

Given series of numbers will form an A.P. if d 1 =d 2 =d 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2

Given series of numbers will form an A.P. if d 1 =d 2 =d 3 ...So, d 1 =a 2 −a 1 =1−1=0d 2 =a 3 −a 3 =2−1=1∵d 1 =d 2 Hence, the given form of numbers will not form an A.P.

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Answered by deb15
0

Answer:

No

Step-by-step explanation:

A sequence is said to be in an AP if it's common difference(d) is same.

so,

1/2 - 3/2 = -1

-1/2 - 1/2 = -1

-3/3 - (-1/2) = -1/2

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