Question

is the smallest number exactly divisible by 20 , 25 , 30​

Answer 1

Answer:

To find the least 5 digit number which is exactly divisible by 20, 25 and 30, we have to find the LCM of 20, 25 and 30

20 = 2*2*5

25 = 5*5

30 = 2*3*5

LCM = 2*2*3*5*5  = 300

So, LCM of 20, 25 and 30 is 300. But we need the least 5 digit number, which is exactly divisible by 20, 25 and 30.  

Least 5 digit number = 10000.

10000 = (33*300) + 100

Next higher quotient is 34.

So, the required number = 34*300   = 10200

Hence, the required number is 10200, which is exactly divisible by 20, 35 and 30