Question

is the solution of root2x²+3xplus root 2=0​

Answer 1

Answer:

Given, 3x2−26x+2=0

⇒x2−326x=−32

⇒x2−326x+(36)2=(36)2−32

⇒x2−2x×36+(36)2=96−32

⇒(x−36

Answer 2

x= -36

x= 36

are the roots of the equation