Question

Is the triangle with sides of length 5 cm, 3 cm,
and 4m, a right-angled triangle? If yes, why?​

Answer 1

Answer:

yes

we have sides 3 4 and 5

so using PGT we have

(longest side)² = (other side)² + ( another side)²

5² =3² +4²

25=9+16

25=25

which is true

hence PGT is applicable

implies triangle is possible

thanks

Answer 2

Answer:

∵ L.H.S = R.H.S

Hence, the given triangle is right-angled

Step-by-step explanation:

The given sides of a triangle-

AB = 5 cm, BC = 3 cm and CA = 4 cm

Show that-

The given triangle is right-angled.

We know that-

In a right-angled triangle, the square of the greatest side is equal to the sum of the square of the two smallest sides.

So, $AB^{2} = BC^{2} + CA^{2}$

L.H.S-

We have,

$AB^{2} = (5)^{2}$

$AB^{2} = 25$

R.H.S-

$BC^{2} + CA^{2} = (3)^{2} + (4)^{2}$

$= 9+16$

$BC^{2} + CA^{2} = 25$

∵ L.H.S = R.H.S

Hence, the given triangle is right-angled triangle.