Question

is the value of "n" when the equation (3m4 + 4m + 5m2 + 4m + n) is divīsible by (m2 + 1)?

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Answer 1

Answer:

Yes it can divisible by me+1

Answer 2

Answer:

The value of n = 2.

Step-by-step explanation:

Given equation 3m⁴ + 4m³ + 5m² + 4m + n is divisible by m² + 1.

⇒ the remainder is zero.

By Factor theorem,  if (x-a) is a factor of polynomial f(x), then f(a) = 0

3m⁴ + 5m² + 4m³ + 4m + n = 0

 

    m² + 1   )  3m⁴ + 4m³ + 5m² + 4m + n ( 3m² + 4m + 2

                    3m⁴ + 0     + 3m²

                 _____________________

                   4m³ + 2m²

                   4m³ + 4m

                -----------------------------------

                  2m² + n

                  2m² + 2

                ----------------------------------

                         n - 2

here reminder is zero

 n - 2 = 0

 n = 2  

therefore the value of n = 2.

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