Is there a graph with degrees 3, 3, 3, 3, 3, 5, 5, 6, 6, 6, 6?
Answers
Answer:
The sum of the degrees is 68, so there must be 34 edges. If the graph is bipartite, the sum of the degrees of the vertices in each part must be 34. Show that this is impossible: there is no way to split the numbers 3,3,3,3,3,5,6,6,6,6,6,6,6,6 into two sets, each summing to 34.
Step-by-step explanation:
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Answer:
There have to be 34 edges when the sum of the degrees is 68. As a reason, there is not a degree in all of these sequences.
Explanation:
The combination of the qualities of the vertices from each part of a graph must be 34. There is no manner to divide the number 3,3,3,3,3,5,6,6,6,6,6,6 into two sets that add to 34, proving that this is a contradiction.
A degree sequence is stated to as pictorial if an uncomplicated graph can be generated with it representing one of the vertex degrees. Using the Havel-Hakimi theorem, the program will connect all stubs without incurring any self-loops if the originating degree sequence is graphics.
There isn't any graph in the sequence. since a legitimate graph can still have negative degrees The list of degrees for each junction in a graph is named the degree sequence. The degrees are normally required from the best levels to the youngest degree in non-increasing order. Noticed that the degree number was never ever decreasing.
So each pair of sets of vertices must also be connected by an edge for one graph to be regarded as complete. Undirected being the up the full graph, which is symbolized by graph vertices
To know more about Graphs, visit:
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To know more about Vertices, visit:
https://brainly.in/question/15349801
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