Is there a Ramond vacuum for real fermions?
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When studying the CFT of a complex fermion ΨΨ we know that if it's periodic, ie if
Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)
then there is a doubly degenerate Ramond vacuum which I denote |±⟩|±⟩.
Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)
then there is a doubly degenerate Ramond vacuum which I denote |±⟩|±⟩.
Answered by
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yes it is......
check the formula i hope that you will understand:-
◆Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)
check the formula i hope that you will understand:-
◆Ψ(σ1+2π,σ2)=Ψ(σ1,σ2)
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