Question

Is there any brainliest who can solve this problem?
If a and b are the two zeroes of
${x }^{2} - 9x + 20$
Find a+b and a-b .
If you answer correctly ,I would mark you as the brainliest .​

Answer 1

Step-by-step explanation:

a+b=9 a-b=-1

I HOPE IT IS RIGHT

Answer 2

Answer:

Given is the quadratic expression in ax^2

+ bx + c form.

And given that a and b are the zeroes .

We know the sum of zeroes = (-b/a)

Here a = 1 , b = -9 & c = 20.

So, ( a + b ) = -(-9/1) = 9 ..............(1).

And , product of zeroes = c/a

= 20/1 = 20 ...............(2).

On subtracting 2 from 1 we have :

=> a + b - ab = 9 - 20.

=> a + b -ab - ab + ab = -11.

=> (a + b - 2ab ) + ab = -11.

=> (a- b)^2 + 20 = -11.

=> (a- b)^ 2 = -31

Therefore a - b = √-31