Question

Is there any class 11 students.......then.....

plz answer 9th qn

Answer 1

Answer:θ⇒30°

Explanation:------------------------------------------------------------

Let the given lines are √3x+y=1 and x+√3y=1.

Name the first line as y=-√3x+1-------(1)

                   Second line as  y=-√1/√3×x+1/√3-----(2)

Find the slope of both  lines.Slope formula=y₂-y₁/x₂-x₁.

From that,line 1 (m1)⇒-√3     and line 2 (m2)=-1/√3

Now apply tan to the slope of the lines.

Tan θ=Ιm₁-m₂/1+m₁m₂Ι   (Tan θ formula)

Tan θ=Ι-√3+1/√3/1+(-√3){-1/√3}Ι

By simplyfying,We get tan θ=1/√3

In tan,We get 1/√3 in 30°.

So the angles between the lines is 30° or 180°-30°=150°

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Thank you!