Is there any class 11 students.......then.....
plz answer 9th qn
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Answer:θ⇒30°
Explanation:------------------------------------------------------------
Let the given lines are √3x+y=1 and x+√3y=1.
Name the first line as y=-√3x+1-------(1)
Second line as y=-√1/√3×x+1/√3-----(2)
Find the slope of both lines.Slope formula=y₂-y₁/x₂-x₁.
From that,line 1 (m1)⇒-√3 and line 2 (m2)=-1/√3
Now apply tan to the slope of the lines.
Tan θ=Ιm₁-m₂/1+m₁m₂Ι (Tan θ formula)
Tan θ=Ι-√3+1/√3/1+(-√3){-1/√3}Ι
By simplyfying,We get tan θ=1/√3
In tan,We get 1/√3 in 30°.
So the angles between the lines is 30° or 180°-30°=150°
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Thank you!
Kartha:
thanku so much dear
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