Math, asked by amirthavarshinims202, 2 months ago

is there any experts here
please answer this
surely i will mark you as brainliest

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Answers

Answered by ritikupadhyay8337
0

Step-by-step explanation:

similarly u can try for other also. u have to break the middle term first and then take the commons and find x .

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Answered by 4fr
0

Answer:

i) x^2 -6x + 3x -18

  x(x-6) + 3(x-6)

  (x-6)(x+3)

ii) x^2 - 8x +15

  x^2 - 5x - 3x + 15

  x(x-5)-3(x-5)

  (x-5)(x-3)

iii) x^2 - 11x + 18

    x^2 - 9x - 2x +18

    x(x-9) -2(x-9)

    (x-9)(x-2)

iv) 2x^2 + 5x +2

   2x^2 +4x + x +2

   2x(x+2)+1(x+2)

   (x+2)(2x+1)

v) 4x^2 +12x + 8

   4x^2 + 8x + 4x + 8

   4x(x+2) + 4(x+2)

    (x+2)(4x+4)

    (x+2)4(x+4)

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