is there any genius who can ANS this with explanation *
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4
Given,
a + √b = whole root of 14+6√5
So, a+√b = whole root 14+6√5
= whole root of 9+5+6√5
= whole root of (3)^2 +(√5)^2 + 2*3*√5
= whole root of (3+√5)^2
= √(3+√5)^2
= 3+√5
Therefore,
a + √b = 3+√5
Comparing both sides,
a = 3 and b = 5
Hence,
a + b = 3+5 = 8
Therefore,
(C) 8 is the final answer for your question.
a + √b = whole root of 14+6√5
So, a+√b = whole root 14+6√5
= whole root of 9+5+6√5
= whole root of (3)^2 +(√5)^2 + 2*3*√5
= whole root of (3+√5)^2
= √(3+√5)^2
= 3+√5
Therefore,
a + √b = 3+√5
Comparing both sides,
a = 3 and b = 5
Hence,
a + b = 3+5 = 8
Therefore,
(C) 8 is the final answer for your question.
asr7:
both of you perfectly answered.
Answered by
3
=> 14 + 6√5 = (a + √b) ²
=> 14 + 6√5 = a² + b + 2a√b
=> 14 + 2(3√5) = a² + b + 2a√b
Comparing values,
a² + b = 14 [neglect, not of use]
a√b = 3√5
××××××××××××
From a√b = 3√5, we get, a = 3 and √b = √5
So, b = 5
=======================
a + b
=> 3 + 5
=> 8
I hope this will help you
(-:
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