Question

Is there any genius who could solve this problem?​

Answer 1

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a² sin(B - C)/(sinB + sinC),

=  a² (sinB cosC - cosB sinC)/(sinB + sinC)

= a² [{(b/k) . (a² + b² - c²)/(2ab)} - {(c² + a² - b²)/(2ca) . (c/k)}]/(b/k + c/k)

= a/(2k) * (a² + b² - c² - c² - a² + b²) * k/(b + c),

= a (b - c) + b (c - a) + c (a - b)

= ab - ca + bc - ab + ca - bc

= 0.

If it is wrong sorry 1

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