Is there any number n for which 6n ends with the digit 0 ? Give reason in =17 .
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If any number ends with the digit zero, it should be divisible by 10 or in other words, it will also divisible by 2 and 5 as 10=2×5.
prime factorisation of 6^n=(2×3)^n
It can be observed that 5 isn't in the prime factorisation of 6^n
Hence, for any value of n, 6^n will not be divisible by 5
Therefore 6^n can't end with the digit zero for any natural number n....
prime factorisation of 6^n=(2×3)^n
It can be observed that 5 isn't in the prime factorisation of 6^n
Hence, for any value of n, 6^n will not be divisible by 5
Therefore 6^n can't end with the digit zero for any natural number n....
vijay11272:
hyyyy
Answered by
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it's right yrrr ...........
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