Is there any real value of 'a' for which the equation x²+ 2x + (a² + 1) = 0 has real roots?
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SOLUTION :
Given : x² + 2x + (a² + 1) = 0
On comparing the given equation with ax² + bx + c = 0
Here, a = 1 , b = 2 , c = (a² + 1)
D(discriminant) = b² – 4ac
D = 2² - 4 × 1 × (a² + 1)
D = 4 - 4(a² + 1)
D = 4 - 4a² - 4
D = - 4a²
D = - 4a² < 0
For real roots , D ≥ 0
Since, D < 0 , so given equation has no real value of 'a' .
Hence, there is no real value of ‘a’ for which the given equation has real roots.
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Answered by
0
Answer:
Thus, No, there is no any real value of a for which the given equation has real roots.
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