IS THERE ANY TRIGONOMETRY EXPERT WHO HAS THE CAPABLITY AND UNDERSTANDING TO SOLVE THIS QUESTION QUICKLY :
IF SIN THETA+COS THETA=√2 SIN(90-THETA), DETERMINE **COT THETA **
SEE CARE FULLY THAT IS SIN THETA AS MOST TIME PEOPLE SEES IT AS COS THETA AND CONVERT IT INTO SIN THETA .????!!!!!!!
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Step-by-step explanation:
sinA+cosA= √2sin(90−A)
=> 1/√2 sinA + 1/√2 cosA= sin (90-A)
=> sinA.cos45° + cosA + sin45°= sin(90-A)
=>(A+45°) = sin(90-A)
Equating
A+45=90−A
⇒2A=45°
⇒A=22× 1/2
A= π/8
∴cotA=cot π/8
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