Question

☑️Is there Anyone Genius to answer both the Parts of this question????☑️


Answer it Correctly!​

Answer 1

Step-by-step explanation:

see attachment

If it helps u plzz mark as brainliest

Answer 2

┏─━─━─━─━∞◆∞━─━─━─━─┓ ✭✮ӇЄƦЄ ƖƧ ƳƠƲƦ ƛƝƧƜЄƦ✮✭

┗─━─━─━─━∞◆∞━─━─━─━─┛

Given :

• AB = PQ

• BC = QR

• Median AM = Median PN

To Prove :

1. △ABM ≅ △PQN
2. △ABC ≅ △PQR

Solution :

1》△ABM ≅△PQN

In △ABM and △PQN

AB = PQ [ given ]

AM = PN [ given ]

BC = QR

half BC = half QR

BM = QN

Therefore, △ABM ≅△PQN [by SSS congruence]

∠ABM = ∠PQN [ by CPCT ]

2》△ABC ≅ △PQR

In △ABC and △PQR

AB = PQ [ given ]

BC = QR [ given ]

∠ABM = ∠PQN [ proved above ]

Therefore, △ABC ≅ △PQR [ by SAS congruence ]

Additionally :

Congruence rule:-

• SSS - If three sides of one triangle are equal to three sides of another triangle, the triangles are congruent.

• SAS - If two sides and the included angle of one triangle are equal to the corresponding sides and angle of another triangle, the triangles are congruent.

• ASA - If two angles and the included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

• AAS - If two angles and the non-included side of one triangle are equal to the corresponding angles and side of another triangle, the triangles are congruent.

• RHS - If the hypotenuse and one leg of one right-angled triangle are equal to the corresponding hypotenuse and leg of another right-angled triangle, the two triangles are congruent.