Question

is there someone ...needed some help.​

Answer 1

Answer:

Step-by-step explanation:here's your answer

Answer 2

Answer:

18

Step-by-step explanation:

The sum of the digits of a two-digit number is 9.

Let the digit of 10 be $a$.

And let the digit of 1 be $b$.

$a+b=9$

∴ $b=9-a$

Nine times this number is twice

the number obtained by reversing the order of the digits.

'This number' means $10a+b$.

'The number obtained by reversing the order of the digits' is $10b+a$.

Substitute $b=9-a$.

$10a+b$ equals $9a+9$.

$10b+a$ equals $-9a+90$.

$9(9a+9)=2(-9a+90)$

$81a+81=-18a+180$

$99a=99$

∴ $a=1$, thus $b=8$

∴ The number is 18.