Is this is right???......
Attachments:

Answers
Answered by
1
Hello Mate!
In your solution I think,
Till the line I drawn is correct, further solution in continuation I am doing.

Hope this time u will understand it frnd.
In your solution I think,
Till the line I drawn is correct, further solution in continuation I am doing.
Hope this time u will understand it frnd.
Attachments:

Similar questions
English,
9 months ago
English,
9 months ago
Science,
9 months ago
Science,
1 year ago
Social Sciences,
1 year ago